displaystylesinleft(x ight)+sin^2left(x ight)=1 ext so, cosleft(x ight)+cos^2left(x ight)=?
= cos x + sin xExplanation: displaystylesinx+sin^2x=1--> displaystylesinx=1-sin^2x(1) displaystylecosx+cos^2x=cosx+left(1-sin^2x ight) ...

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sine, x, equals, 1, minus, sine, squared, x(1) cosine, x, plus, cosine, squared, x, equals, cosine, x, plus, left parenthesis, 1, minus, sine, squared, x, right parenthesis ..." role="text" class="MathExpression_mathExpression__22QI1 ">
Noah G Nov 2, 2016 We will need the following identities khổng lồ solve sầu this equation. displaystyle•cos^2x=1-sin^2xdisplaystyle•cos2x=1-2sin^2x ...
How bởi vì you solve displaystylecos^2left(x ight)-sin2left(x ight)=sin^2left(x ight) ?
displaystylex=fracnpi2+fracpi8 , n = 0, 1, 2, ... Explanation:Rearranging,displaystylesinleft(2x ight)=cos^2x-sin^2x=cosleft(2x ight) ...
How khổng lồ solve sầu the equation displaystylecos^4left(x ight)-sin^4left(x ight)=1+sinleft(2x ight) ?
displaystylex=npi ext ordisplaystyle ext x=npi-fracpi4 ext for any integerdisplaystylen Explanation:Given: displaystylecos^4left(x ight)-sin^4left(x ight)=1+sinleft(2x ight) ...
2cos ^2left(x ight)-2cos left(x ight)=sin ^2left(x ight),:0le :xle :2pi Subtract sin ^2(x) from both sides: 2cos ^2left(x ight)-2cos left(x ight)-sin ^2left(x ight)=0 ...

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Truong-Son N. Aug 6, năm ngoái It's not that bad: displaystyle=cosxleft(cos^2x+sin^2x ight)displaystyle=left(cosx ight) since there ...
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left< eginarray l l 2 & 3 \ 5 & 4 endarray ight> left< eginarray l l l 2 và 0 và 3 \ -1 và 1 & 5 endarray ight>
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